边框风格只有简单几种
如果想要边框颜色是彩色就没有办法了
其实可以利用动态创建rectangle更改数据窗口列边框颜色适用free格式(不需要穿外套列tag值设为0)global type gf_
bordercolor from function_objectend
typeforward prototypesglobal subroutine gf_bordercolor
(datawindow adw, long al_bodercolor)end prototypesglobal
subroutine gf_bordercolor (datawindow adw,
long al_bodercolor);//rectangle(band=detail x="599"
y="260" height="88" width="288" name=r_1
brush.hatch="7" brush.color="1627389951
" pen.style="0" pen.width="5"
pen.color="8421376" background.mode="1"
background.color="553648127" )Integer
iString ls_syntaxFor i = 1 To Integer
(adw.Object.DataWindow.Column.Count)If
adw.Describe("#"+String(i)+".Visible") = '1'
and adw.Describe(ls_objects[i]+".tag")
<> '0' Thenls_syntax 
" create rectangle
(band="+adw.Describe("#"+String(i)+".Band")
+" "ls_syntax ' x="'+ String(Integer
(adw.Describe("#"+String(i)+".X")) - 4)
+'"'ls_syntax ' y="'+ String(Integer
(adw.Describe("#"+String(i)+".Y")) - 4)
+'"'ls_syntax ' Height="'+ String
(Integer(adw.Describe("#"+String(i)+".Height")) + 8)
+'"'ls_syntax ' Width="'+ String
(Integer(adw.Describe("#"+String(i)+".Width")) + 8)
+'"'ls_syntax ' name=RBorder_'+ adw.Describe
("#"+String(i)+".Name")ls_syntax '
brush.hatch="7" brush.color="1627389951"
pen.style="0" pen.width="5"
pen.color="'+String(al_bodercolor)
+'" background.mode="1" background.color="553648127" )
'End IfNextadw.Mod
y
(ls_syntax)end subroutine
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