silverlight:Silverlight 画分形(Koch曲线)

  Koch曲线是类平面曲线:从条线段中间 3分的部分用等边 3角形两条边代替形成图形有 4条边 5个节点再依次组成边每条线段做相同处理

  迭代如图:

Silverlight 画分形(Koch曲线)

  稍微变换画成 6边形凸起方向向两边用随机颜色画完后为雪花状

  代码:

private void LayoutRoot_Loaded(object sender, RoutedEventArgs ea)
{
  double sqrt3 = Math.Sqrt(3);
  Po a = Po(50, (float)(100 + 50 * sqrt3));
  Po b = Po(100, (float)(100 + 100 * sqrt3));
  Po c = Po(200, (float)(100 + 100 * sqrt3));
  Po d = Po(250, (float)(100 + 50 * sqrt3));
  Po e = Po(200, 100);
  Po f = Po(100, 100);
  line(a, b, 5);
  line(b, a, 5);
  line(b, c, 5);
  line(c, b, 5);
  line(c, d, 5);
  line(d, c, 5);
  line(d, e, 5);
  line(e, d, 5);
  line(e, f, 5);
  line(f, e, 5);
  line(f, a, 5);
  line(a, f, 5);
}
private void line(Po a, Po b, n)
{
   (n > 0)
  {
    double r = Math.Atan(Math.Abs(a.Y - b.Y) / Math.Abs(a.X - b.X)); //角度
    double v = 0;
    Po c = Po(a.X + (b.X - a.X) / 3, a.Y + (b.Y - a.Y) / 3);
    Po d = Po(a.X + 2 * (b.X - a.X) / 3, a.Y + 2 * (b.Y - a.Y) / 3);
    double l = Math.Sqrt((c.X - d.X) * (c.X - d.X) + (c.Y - d.Y) * (c.Y - d.Y));
    Po e;
     (b.Y - a.Y >= 0 && b.X - a.X > 0)
    {
      v = r;
    }
     (b.Y - a.Y > 0 && b.X - a.X <= 0)
    {
      v = Math.PI - r;
    }
     (b.Y - a.Y <= 0 && b.X - a.X < 0)
    {
      v = Math.PI + r;
    }
     (b.Y - a.Y < 0 && b.X - a.X >= 0)
    {
      v = 2 * Math.PI - r;
    }
    e = Po((float)(l * Math.Cos(v + Math.PI / 3) + c.X), (float)(c.Y + l * Math.Sin(v + Math.PI / 3)));
    line(a, c, n - 1);
    line(c, e, n - 1);
    line(e, d, n - 1);
    line(d, b, n - 1);
  }
  
  {
    Line l = Line;
    Random rnd = Random;
    Color c = Color.FromArgb(255, ()rnd.Next(255), ()rnd.Next(255), ()rnd.Next);
    l.Stroke = SolidColorBrush(c);
    l.X1 = a.X;
    l.Y1 = a.Y;
    l.X2 = b.X;
    l.Y2 = b.Y;
    LayoutRoot.Children.Add(l);
  }
}
运行结果如图:

Silverlight 画分形(Koch曲线)

  Koch曲线部分都由4个跟它自身比例为1:3形状相同小曲线组成那么它豪斯多夫维数(分维数)为d=log(4)/log(3) =1.26185950714...

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